Monday, 9 December 2013
Assessed Homework
1. (a) points
plotted correctly;; [Deduct 1 mark
for each error] 2
[Line not necessary]
[Line not necessary]
(b) 3
(m/s); 1
(c) (i) acceleration = change in velocity / time taken; 1
[Accept a = (v-u)/t
[Accept a = (v-u)/t
(ii) acceleration
= 3/15 ; [Allow ecf from part (b)]
= 0.2 (m/s2); 2
= 0.2 (m/s2); 2
[6]
2. C
[1]
3. (i) acceleration (due to gravity) /
gravitational field strength 1
(ii) m
/ s2 or N / kg 1
[2]
4. (a) A description to include:
1. upward push/reaction/thrust;
2. of the ground on the athlete; 2
2. of the ground on the athlete; 2
(b) (i) A calculation to include:
1. acceleration = (v-u)/t
2. substitution of correct data,
3. = 9.7 m/s2; [Accept –9.7 m/s2] 3
2. substitution of correct data,
3. = 9.7 m/s2; [Accept –9.7 m/s2] 3
(ii) downwards;
negative gradient/backwards slope/athlete slowing down/retardation/
deceleration; 2
negative gradient/backwards slope/athlete slowing down/retardation/
deceleration; 2
(iii) A calculation to include:
1. F =
ma;
2. = 65 kg ´ 9.7 (m/s2);[Allow ecf from b(iii)]
3. = 630 – 633 (N);
[Accept either 65 ´ 10 m/s2 = 650 N for 2 marks
or 65 ´ 9.81 m/s2 = 638 N for 2 marks] 3
2. = 65 kg ´ 9.7 (m/s2);[Allow ecf from b(iii)]
3. = 630 – 633 (N);
[Accept either 65 ´ 10 m/s2 = 650 N for 2 marks
or 65 ´ 9.81 m/s2 = 638 N for 2 marks] 3
(iv) downward pull of the Earth/gravitational
pull;
[Reject gravity] 1
[Reject gravity] 1
[11]
5. (a) 15 (m/s) 1
(b) acceleration = change in speed ÷ time;
= 15 m/s ÷ 1.5 s;
= 10 m/s2; 3
= 15 m/s ÷ 1.5 s;
= 10 m/s2; 3
(c) (i) the acceleration decreases
(ii) this is shown by the decreasing slope/
gradient of the graph 2
(d) at
Pisa, air resistance affected the objects ;
the lighter object was affected more than the heavy one
there is no air on the Moon, so both objects had the same
acceleration/ neither object was affected by air resistance 3
the lighter object was affected more than the heavy one
there is no air on the Moon, so both objects had the same
acceleration/ neither object was affected by air resistance 3
[9]
6. (a) resultant/net/unbalanced force is in
forwards direction
/950>550 /driving force>resistive force/
forwards force is greater than backwards force; 1
/950>550 /driving force>resistive force/
forwards force is greater than backwards force; 1
(b) Ignore F = ma (or in words)
acceleration = force/mass;
= 400 (N) / 850 (kg);
= 0.47 (m/s2); 3
Bald 0.5 gains no marks
If acceleration = 1.12 (m/s2) award TWO marks maximum only
acceleration = force/mass;
= 400 (N) / 850 (kg);
= 0.47 (m/s2); 3
Bald 0.5 gains no marks
If acceleration = 1.12 (m/s2) award TWO marks maximum only
(c) the
driving force becomes zero; Accept decreases OWTTE;
the overall resistive force increases/braking force is added/air
resistance decreases;
plus 1 communication mark for ensuring that spelling,
punctuation and grammar are accurate, so that the meaning is clear; 3
the overall resistive force increases/braking force is added/air
resistance decreases;
plus 1 communication mark for ensuring that spelling,
punctuation and grammar are accurate, so that the meaning is clear; 3
[7]
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