This is for the whole year.. You won't be examined on topics we have yet to do.
http://twyfordigcsephysics.blogspot.co.uk/p/revision.html
Tuesday, 13 May 2014
Friday, 9 May 2014
Mark Scheme assessed homework
1. (a) friction if
more than one box is ticked, award 1
(L3)
no mark
no mark
(b) (i) it
gets longer accept
‘it is more’ 1
(L3)
(ii) any one from 1
(L4)
· there is less friction or grip
· the road is slippery accept ‘water is a lubricant’
(iii) it gets longer accept ‘it is more’ 1 (L3)
(iv) concrete 1
(L4)
[5]
2. (a) one mark is for the correct value and
the other mark is for the corresponding unit
either
· 1500 accept
‘100 × 15’ 1
(L7)
· N cm or newton cm 1
(L7)
or
· 15 accept
‘100 × 0.15’
· N m or newton metre
(b) exert
a larger force answers
may be in either order 1
(L7)
accept
‘use a bigger force’ or ‘push harder’
do not accept ‘exert a larger pressure’
do not accept ‘exert a larger pressure’
exert the force further away from the
nut 1
(L7)
accept
‘push down further from the nut’ or ‘exert the force further along the
spanner’
do not accept ‘use of a longer spanner’
do not accept ‘use of a longer spanner’
[4]
3. (a) down 1
(L3)
(b) B and D letters
may be in either order both 1
(L3)
letters are required for the mark
letters are required for the mark
accept
112 and 112
(c) down 1
(L3)
(d) E 1
(L3)
(e) any two from 2
(L4)
· put the gold coin in one pan and a silver
coin or coins in the other
· add or replace or remove silver
coins
· see which pan goes up or see which way
the scales move
accept
‘see if it balances’
· it is heavier than the silver coins which go
up
· it is lighter than the silver coins which go
down
accept
‘try each silver coin to see which one balances the gold coin’ for two marks
[6]
4. (a) (i) 75 accept
‘50 × 1.5’ 1
(L7)
Nm 1 (L7)
Nm 1 (L7)
do
not accept lower case n
(ii) 750 accept
‘
‘ or ‘50 × 15’ 1
(L7)
accept the numerical answer to part (i) ÷ 0.1

accept the numerical answer to part (i) ÷ 0.1
(b) any
one from 1
(L7)
· a current flows in the coil
· the coil or the iron core accept ‘there is a magnetic field’ or ‘the
becomes magnetised electromagnet switches on
· a current flows in the coil
· the coil or the iron core accept ‘there is a magnetic field’ or ‘the
becomes magnetised electromagnet switches on
do
not accept ‘the core becomes magnetic’
any one from 1
(L7)
· the counterweight is attracted
to the coil or core or the
electromagnet
· the electromagnet produces a accept ‘the left-hand side of the barrier
bigger moment moves down’
· the counterweight is attracted
to the coil or core or the
electromagnet
· the electromagnet produces a accept ‘the left-hand side of the barrier
bigger moment moves down’
‘the
right-hand side moves up’ is insufficient
[5]
5. (i) (when
a system is in equilibrium) the sum of the anticlockwise
moments equals the sum of the clockwise moments (about the same pivot) B1
moments equals the sum of the clockwise moments (about the same pivot) B1
(ii) sum of the forces equals zero / resultant
force is zero B1
sum of the moments equals zero B1
sum of the moments equals zero B1
[3]
6. (sum of) clockwise moment(s) = (sum of )
anticlockwise moment(s)
anticlockwise moment(s)
Not:
‘CWM = ACWM’
C1
(18 × 0.14) + (60 + 0.32) = 0.035F
Allow:
working in consistently in cm
C1
F ≈ 620 (N)
Note:
Bald answer scores 3 marks
Allow: 1 mark for 21.72 (N m) or 2172 (N cm)
Allow: 1 mark for 21.72 (N m) or 2172 (N cm)
A1
[3]
7.
(a) Any three from:
1. (Suspend plate from a point and then) mark a
vertical line on the plate (wtte)
2. Plumb line / ‘pendulum’ (used to find the vertical
line)
3. Hang from another point / place (and draw
another vertical line) (wtte)
4. Where the lines intersect gives position of centre
of gravity (wtte)
1. (Suspend plate from a point and then) mark a
vertical line on the plate (wtte)
2. Plumb line / ‘pendulum’ (used to find the vertical
line)
3. Hang from another point / place (and draw
another vertical line) (wtte)
4. Where the lines intersect gives position of centre
of gravity (wtte)
Note:
For 1st point accept ‘mark line of string’
Allow:
1 mark for ‘By trial and error find a position where the plate balances’
B1 × 3
(b) (i) moment = 6.0 × 0.40
moment = 2.4 (N m)
moment = 2.4 (N m)
B1
(ii) Weight / force acts through the pivot
Or (perpendicular) distance from pivot is (reduced to)
zero (wtte)
Or (perpendicular) distance from pivot is (reduced to)
zero (wtte)
Allow:
weight is ‘vertically below’/‘directly below’ the pivot
Reference to pivot / point P (wtte) is essential
Reference to pivot / point P (wtte) is essential
B1
[5]
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